If two bulbs are added to the original circuit with one cell and one bulb, what will the new current be?

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When additional components, such as bulbs, are added to a circuit connected to a single power source, the overall resistance of the circuit changes, which in turn affects the current flowing through it.

In a simple series circuit with one bulb, the current is determined by the voltage of the power source and the resistance of the bulb. When a second bulb is added in series, the total resistance of the circuit increases because the resistances of the bulbs add together. Using Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R), we can deduce that as resistance increases, the overall current flowing through the circuit will decrease.

In this scenario, the original circuit had a certain current, and by adding two bulbs, we effectively increase the total resistance and decrease the current. If the original current was 0.2A with one bulb, then with two bulbs, the current might reduce to around 0.1A due to the increased resistance.

Thus, it can be understood that adding two bulbs in series causes the current to drop, making the new current 0.1A a logical conclusion based on these principles.

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