What happens to the current if both another cell and another bulb are added to a circuit with one cell and one bulb, originally at 0.2A?

In a series circuit, when more components such as cells and bulbs are added, the total resistance in the circuit increases. This is because each component adds additional resistance to the flow of current. According to Ohm's law, which states that current (I) is equal to voltage (V) divided by resistance (R), if the resistance increases while the voltage remains the same (as when adding another bulb and cell), the overall current must decrease or remain the same depending on the configuration of the circuit.

In this case, the initial current is 0.2A. By adding another bulb, the resistance increases. If the additional cell is also in series with the original cell, it may provide additional voltage, but typically in simple circuits at this level, we equate how additional components will balance out to affect the flowing current through increased resistance. Therefore, if the total voltage from the cells doesn't sufficiently overcome the total resistance increase caused by adding another bulb, the current may still remain relatively unchanged.

This leads us to understand why the current stays at 0.2A. The addition of the components does not create a situation conducive to an increase in current due to the simultaneous increase in resistance caused by the added bulb. Thus, this answer accurately